Math, asked by vidhyaaarthi, 1 year ago

A man sold 2 articels at rupees wit each.on the first article he gained 25%and in the other he lost 25%. How much does he gain or loss in the whole transaction. Also finding it gain or loss percentage in whole transaction.

Answers

Answered by meyyappan
1
SP of first article = Rs 375

Gain % = 25%

Let the CP of the article be Rs x.

25=(375-x)/x×100
(375-x)/x=25/100
=1/4
therefore x=300
∴ CP of first article = Rs 300

 

SP of second article = Rs 375

Loss % = 25%

Let the CP of the second article be Rs y.

25=(y-375)/y×100
(y-375)/y=25/100
=1/4
therefore y=500

∴ CP of second article = Rs 500

∴ Combined CP of 2 articles = 300 + 500 = Rs 800

Combined SP of 2 articles = 375 + 375 = Rs 750

As CP > SP, this is a case of loss.

loss%=(cp-sp)/cp ×100
=(800-750)/800. ×100
= 6.25%

Answered by TheBrainliestUser
2

Solution :-

We have,

Selling price of two articles is Rs 375 each.

Cost Price of one article at 25% gain :

C.P = (S.P × 100)/(100 + gain)

= (375 × 100)/(100 + 25)

= 37500/125

= 300

Cost price of other article at 25% loss :

C.P = (S.P × 100)/(100 - loss)

= (375 × 100)/(100 - 25)

= 37500/75

= 500

Now,

Cost Price of two articles = Rs (300 + 500) = Rs 800

Selling price of two articles = Rs (375 + 375) = Rs 750

Cost Price > Selling price

Loss = C.P - S.P

= Rs (800 - 750)

= Rs 50

Loss % = (loss × 100)/C.P %

= (50 × 100)/800 %

= 5000/800 %

= 6.25%

Answer : The loss percent in the whole transaction = 6.25%

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