A man sold 2 Tv set for rs. 3420 on first he gained 25% and on second he suffered a loss of 10%. Find overall profit or loss if cost price of second Tv is same as selling price of first TV
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Hi ,
Selling price of 2 T.V sets = Rs3420
Let the cost price of first T.V (cp1) = Rs x
i ) c.p1= Rs x
gain ( g ) = 25%
s.p1= cp1 ( 100 + g )/100
= x [ 100 + 25 ]/100
= 5x/4 ----( 1 )
ii ) c.p of second TV (cp2) = sp1
cp2 = 5x/4
loss ( l ) = 10%
sp2 =( cp2)( 100 - l )/100
= (5x/4 )( 100 - 10 )/100
= (5x/4)(9/10)
sp2= 9x/8 ---( 2 )
iii ) Total selling price of 2 T.V sets
= ( 1 ) + ( 2 )
= 5x/4 + 9x/8
= ( 10x + 9x )/8
= 19x/8------( 3 )
But Given Selling price = Rs 3420
19x/8 = 3420 [ from ( 3 ) ]
=> x = ( 3420 × 8 )/19
x = 1440 -------( 4 )
Now ,
total cost price of 2 t.v sets =
= cp1 + cp2
= x + 5x/4
= ( 4x + 5x )/4
= 9x/4
= ( 9 × 1440)/4 [ from ( 4 ) ]
= 3240
Total c.p of 2 t.v sets = Rs 3240
Total sp = Rs 3420
Total sp > total CP
He gets profit .
overall gain =total sp - total CP
= Rs 3420 - Rs 3240
= Rs 180
Therefore ,
He gets overall profit
Rs 180
I hope this helps you.
: )
Selling price of 2 T.V sets = Rs3420
Let the cost price of first T.V (cp1) = Rs x
i ) c.p1= Rs x
gain ( g ) = 25%
s.p1= cp1 ( 100 + g )/100
= x [ 100 + 25 ]/100
= 5x/4 ----( 1 )
ii ) c.p of second TV (cp2) = sp1
cp2 = 5x/4
loss ( l ) = 10%
sp2 =( cp2)( 100 - l )/100
= (5x/4 )( 100 - 10 )/100
= (5x/4)(9/10)
sp2= 9x/8 ---( 2 )
iii ) Total selling price of 2 T.V sets
= ( 1 ) + ( 2 )
= 5x/4 + 9x/8
= ( 10x + 9x )/8
= 19x/8------( 3 )
But Given Selling price = Rs 3420
19x/8 = 3420 [ from ( 3 ) ]
=> x = ( 3420 × 8 )/19
x = 1440 -------( 4 )
Now ,
total cost price of 2 t.v sets =
= cp1 + cp2
= x + 5x/4
= ( 4x + 5x )/4
= 9x/4
= ( 9 × 1440)/4 [ from ( 4 ) ]
= 3240
Total c.p of 2 t.v sets = Rs 3240
Total sp = Rs 3420
Total sp > total CP
He gets profit .
overall gain =total sp - total CP
= Rs 3420 - Rs 3240
= Rs 180
Therefore ,
He gets overall profit
Rs 180
I hope this helps you.
: )
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