Math, asked by Sivapriya49, 8 months ago

a man sold a chair and a table together for ₹12000 gaining 10% on the chair and 15% on the table .Had he sold them for ₹11625 the profit% would have interchanged . Find the cost price of them​

Answers

Answered by Anonymous
34

Answer:

hi dear...

here is ur answer

Step-by-step explanation:

☆Given:

A man sold a chair and a table together for RS 12000 profit a 10% on the chair and 15% on the table.

If  he sold them for RS 11625,the profit% would have interchanged.

☆To Find:

The Cost price of each article.

☆Solution:

1) Let the cost price of the chair is 100C and table is 100T.

2) So according the first case the Selling price of the chair is 110C and of table is 115T.

115T + 110C = 12000-----------(i)

3) According the first case the Selling price of the chair is 115C and of table is 110T.

110T + 115C = 11625-------------(ii)

4) Add the equation (i) and (ii) we get

225T + 225C = 23625

T + C = 23625/225

T + C = 105------------(iii)

5) Subtract the equation (i) and (ii) we get

5T - 5C = 375

T - C = 375/5

T - C = 75 -------------(iv)

6) On Adding (iii) and (iv) we get

2T = 180

T = 90

Cost price of table is 100T = ₹ 9000

7) Putting the value of T in any equation we get the value of C as 15

Cost price of chair is 100C = ₹1500

The Cost price of each article are ₹ 9000 and  ₹1500.

have a nice day

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