A man sold a chair and a table together for ₹1520 thereby making a profit of 25% on the chair and 10% on the table. By selling them together ₹1534 he would have made a profit of 10% on the chair and 25% on table. Find the cost price of each.
Answers
Answer:We need to find the cost price of each.
Let the cost price of chair = x.
Let the cost price of table = y.
Condition 1:
Profit on the chair = 25%.
Selling price of chair = x + 25x/100
= 125x/100.
Profit on the table = 10%.
Selling price of table = x + 10/100
= 110x/100.
Given that Total selling price = 1520
125x/100 + 110x/100 = 1520
125x + 110x = 1520 * 100
125x + 110x = 152000
25x + 22y = 30400 ------------------------ (1)
Condition 2:
Profit on the chair =10%.
Selling price of the chair = x + 10x/100
= 110x/100
Profit on the table = 25%
Selling price of the table = y + 25y/100
= 125y/100.
Given that total selling price = 1535
110x/100 + 125y/100 = 1535
110x + 125y = 153500
22x + 25y = 30700 --------------------------- (2)
On solving (1) * 22 & (2) * 25, we get
550x + 484y = 668800
550x + 625y = 767500
------------------------------------
-141y = -98700
y = 700.
Substitute y = 700 in (2), we get
22x + 25y = 30700
22x + 25 * 700 = 30700
22x + 17500 = 30700
22x = 13200
x = 13200/22
x = 600.
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