Math, asked by copo, 30 days ago

A man sold a chair and table for ₹12000 gaining 10% on chair and 15% on table. Had he sold the for 11625, the profit would've interchanged. Find the C.P.
I want to see how can we find it by adding and subtracting the coefficients. no copy paste​​

Answers

Answered by tennetiraj86
2

Step-by-step explanation:

Given :-

A man sold a chair and table for ₹12000 gaining 10% on chair and 15% on table. Had he sold the for 11625, the profit would've interchanged.

To find :-

Find the C.P. of each item ?

Solution :-

Let the Cost price of the chair be Rs. X

Let the Cost Price of the table be Rs. Y

Profit on the chair = 10% of the CP

=> Profit = 10% of X

=> Profit = (10/100)×X

=> Profit = 10X/100

=> Profit = Rs. X/10

We know that

Selling Price = Cost Price + Profit

=> SP = X+(X/10)

=>SP = (10X+X)/10

=> SP of the chair = Rs. 11X/10 ----------(1)

Profit on the table = 15% of the CP

=> Profit = 15% of Y

=> Profit = (15/100)×Y

=> Profit = 15Y/100

=> Profit = Rs. 3Y/20

We know that

Selling Price = Cost Price + Profit

=> SP = Y+(3Y/20)

=>SP = (20Y+3Y)/20

=> SP of the table = Rs. 23Y/20 ----------(2)

According to the given problem

A man sold a chair and table for ₹12000 gaining 10% on chair and 15% on table.

=> (11X/10)+(23Y/20) = 12000

LCM of 10 and 20 = 20

=> (22X+23Y)/20 = 12000

=> 22X+23Y = 12000×20

=> 22X+23Y = 240000 ----------(3)

If he sold it for Rs. 11625 the profit Percentages are interchanged

=> Profit on chair = 15% of CP

=> Profit = 15% of X

=> Profit = (15/100)×X

=> Profit = 15X/100

=> Profit = Rs. 3X/20

We know that

Selling Price = Cost Price + Profit

=> SP = X+(3X/20)

=>SP = (20X+3X)/20

=> SP of the table = Rs. 23X/20 ----------(4)

Profit on the table = 10% of the CP

=> Profit = 10% of Y

=> Profit = (10/100)×Y

=> Profit = 10Y/100

=> Profit = Rs. Y/10

We know that

Selling Price = Cost Price + Profit

=> SP = Y+(Y/10)

=>SP = (10Y+Y)/10

=> SP of the chair = Rs. 11Y/10 ----------(5)

According to the given problem

=> ( 23X/20) + (11Y/10) = 11625

LCM of 10 and 20 = 20

=> (23X+22Y)/20 = 11625

=> 23X+22Y = 11625×20

=> 23X+22Y = 232500 ----------(6)

On adding (3) and (6)

22X+23Y = 240000

23X+22Y = 232500

(+)

_______________

45X+45Y = 472500

_______________

=> 45X+45Y = 472500

=> 45(X+Y) = 472500

=> X+Y = 472500/45

=> X+Y = 10500-----------(7)

On subtracting (6) from (3)

22X+23Y = 240000

23X+22Y = 232500

(-)

_______________

-X+Y = 7500

_______________

=>- X+Y = 7500

=> X-Y = -7500 ----------(8)

On adding (7)&(8)

X+Y = 10500

X-Y = 7500

(+)

___________

2X+0 = 3000

___________

=> 2X = 3000

=> X = 3000/2

=> X = 1500

On Substituting the value of X in (7) then

=> 1500+Y = 10500

=>Y = 10500-1500

=> Y = 9000

Therefore, X = Rs. 1500 and Y = Rs. 9000

Answer:-

The Cost Price of the chair = Rs. 1500

The Cost Price of the table = Rs. 9000

Used formulae:-

  • Selling Price > Cost Price = Profit

  • Selling Price = Cost Price + Profit
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