Math, asked by valda, 1 year ago

a man sold a chair and table together for rupees 1520 nearby making profit of 25% on the chair and 10% on the table .By selling them together for Rs. 1535 he would have a profit of 10% on the chair and 25% on the table .find the cost price of table and chair.

Answers

Answered by ROCKSTARgirl
20
We need to find the cost price of each.

Let the cost price of chair = x.

Let the cost price of table = y.

Condition 1:

Profit on the chair = 25%.

Selling price of chair = x + 25x/100

                                   = 125x/100.

Profit on the table = 10%.

Selling price of table = x + 10/100

                                    = 110x/100.

Given that Total selling price = 1520

125x/100 + 110x/100 = 1520

125x + 110x = 1520 * 100

125x + 110x = 152000

25x + 22y = 30400     ------------------------ (1)

Condition 2:

Profit on the chair =10%.

Selling price of the chair = x + 10x/100

                                          = 110x/100

Profit on the table = 25%

Selling price of the table = y + 25y/100

                                          = 125y/100.

Given that total selling price = 1535

110x/100 + 125y/100 = 1535

110x + 125y = 153500

22x + 25y = 30700       --------------------------- (2)

On solving (1) * 22 & (2) * 25, we get

550x + 484y = 668800

550x + 625y = 767500

------------------------------------

          -141y = -98700

              y = 700.

Substitute y = 700 in (2), we get

22x + 25y = 30700

22x + 25 * 700 = 30700

22x + 17500 = 30700

22x = 13200

x = 13200/22

x = 600.

Therefore the cost price of chair = 600 rupees.

                  the cost price of table = 700 rupees.

Hope this helps!   --------------------- Gud Luck
Answered by Ashish2716
2

Step-by-step explanation:

We need to find the cost price of each.

Let the cost price of chair = x.

Let the cost price of table = y.

Condition 1:

Profit on the chair = 25%.

Selling price of chair = x + 25x/100

                                   = 125x/100.

Profit on the table = 10%.

Selling price of table = x + 10/100

                                    = 110x/100.

Given that Total selling price = 1520

125x/100 + 110x/100 = 1520

125x + 110x = 1520 * 100

125x + 110x = 152000

25x + 22y = 30400     ------------------------ (1)

Condition 2:

Profit on the chair =10%.

Selling price of the chair = x + 10x/100

                                          = 110x/100

Profit on the table = 25%

Selling price of the table = y + 25y/100

                                          = 125y/100.

Given that total selling price = 1535

110x/100 + 125y/100 = 1535

110x + 125y = 153500

22x + 25y = 30700       --------------------------- (2)

On solving (1) * 22 & (2) * 25, we get

550x + 484y = 668800

550x + 625y = 767500

------------------------------------

          -141y = -98700

              y = 700.

Substitute y = 700 in (2), we get

22x + 25y = 30700

22x + 25 * 700 = 30700

22x + 17500 = 30700

22x = 13200

x = 13200/22

x = 600.

Therefore the cost price of chair = 600 rupees.

                  the cost price of table = 700 rupees.

Hope this helps!   --------------------- Gud Luck

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