Math, asked by sri6939, 1 year ago

a man sold a horse at a loss of 7% had he been able to sell it at a gain of 9% it would have fetched rs 65 more than it did what was the cost price​

Answers

Answered by hduejn
13

Answer: let principle be x

amount at 7 percent loss = x - 7x/100

= 93/100 x

amount at 9 percent gain = x + 9/100 x

109/100 x

A/Q 109/100x - 93/100 x = 65 rs

16/100 x = 65

x = 65*100/16

x = 406.25

Step-by-step explanation:

Answered by sadiaanam
0

Answer: Cost price of the horse was 400 rupees.

Step-by-step explanation:

To solve this problem, we can use algebra.

Let's call the cost price of the horse "x". Then, if the man sold the horse at a loss of 7%, the selling price would be x - 0.07x = 0.93x. And if the man had been able to sell the horse at a gain of 9%, the selling price would be x + 0.09x = 1.09x.

We know that in the latter case, the selling price would have been 65 rupees more than it actually was, so we can set up the following equation:

0.93x + 65 = 1.09x

Next, we can isolate x by subtracting 0.93x from both sides of the equation:

65 = 0.16x

Finally, we can solve for x by dividing both sides of the equation by 0.16:

x = 400

So the cost price of the horse was 400 rupees.

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