Question

A man sold a mobile phone for Rs. 6251 and lost 1/20 of the cost price. find the cost price of the mobile phone and loss percent.

Answer 1

SP = Rs.6251

CP = 6251 x 20/19 = Rs.6580

Loss = 6580 - 6251 = Rs.329

Percent = 329/6580  x 100 = 5%

Answer 2

The cost price of the mobile phones is Rs.6580 and loss percent is 5%.

Step-by-step explanation:

Given : A man sold a mobile phone for Rs. 6251 and lost $\frac{1}{20}$ of the cost price.

To find : The cost price of the mobile phone and loss percent ?

Solution :

Let the cost price be 'x'.

The selling price is Rs.6251

Loss is $\frac{1}{20}$ of the cost price i.e. $L=\frac{1}{20}x$

Loss = Cost price - Selling price

$\frac{1}{20}x=x-6251$

$x=20x-125020$

$19x=125020$

$x=\frac{125020}{19}$

$x=6580$

Cost price is Rs. 6580.

Loss is $L=\frac{1}{20}\times 6580$

$L=329$

The loss is Rs.329.

The loss percentage is given by,

$L\%=\frac{L}{CP}\times 100$

$L\%=\frac{329}{6580}\times 100$

$L\%=5\%$

Therefore, the cost price of the mobile phones is Rs.6580 and loss percent is 5%.

#Learn more

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