Question

A man sold a second hand bike at ₹50,000 at a loss of 15% find the CP

​

Answer 1

Answer:

Let the C.P. of the 1

st

scooter = Rs. x.

Then, C.P. of the 2

nd

scooter = Rs. (18000−x)

S.P. of 1

st

scooter = Rs. x×

100

125

= Rs.

4

5x

S.P. of 2

nd

scooter = Rs. (18000−x)×

100

80

= Rs.

5

4

(18000−x)

Since Mohan neither gains nor loses, his total S.P. = Total C.P.

⇒

4

5x

+

5

4

(18000−x)=18000

⇒

4

5x

−

5

4x

=18000−14400=3600

⇒

20

25x−16x

=3600⇒9x=3600×20

⇒x=

9

3600×20

=8000

∴ C.P. of 1

st

scooter = Rs. 8000

C.P. of 2

nd

scooter = Rs. 10,000.

Step-by-step explanation:

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