A man sold a table and chair together for rupees 850 at a loss of 10% on the table and a gain of 10% on the chair by selling from together for rupees 950 he would made a gain of 10% on the table and loss of 10% on the chair find the cost price of each
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let the cost of the chair be 'x' and the cost of the table be 'y’
in case 1
gain on chair = (10/100) *x
= x/10
loss on table = (10/100) * y
= y/10
⇒ (x + x/10) + (y - y/10) = 850
⇒ (11x/10) + (9y/10) = 850
⇒ 11x + 9y = 8500............... 1
in case 2
⇒ (x - x/10) + (y + y/10) = 950
9x + 11y = 9500 ................. 2
after solving equations 1 and 2 we will get
x = 200 and y = 700
∴cost of the chair is Rs 200 and the cost of the table is Rs 700
in case 1
gain on chair = (10/100) *x
= x/10
loss on table = (10/100) * y
= y/10
⇒ (x + x/10) + (y - y/10) = 850
⇒ (11x/10) + (9y/10) = 850
⇒ 11x + 9y = 8500............... 1
in case 2
⇒ (x - x/10) + (y + y/10) = 950
9x + 11y = 9500 ................. 2
after solving equations 1 and 2 we will get
x = 200 and y = 700
∴cost of the chair is Rs 200 and the cost of the table is Rs 700
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