Question

A man sold a table and chair together for rupees 850 at a loss of 10% on the table and a gain of 10% on the chair by selling from together for rupees 950 he would made a gain of 10% on the table and loss of 10% on the chair find the cost price of each

Answer 1

let the cost of the chair be 'x' and the cost of the table be 'y’
in case 1
gain on chair = (10/100) *x
                       = x/10
loss on table = (10/100) * y
                      = y/10
⇒ (x + x/10) + (y - y/10) = 850
⇒ (11x/10) + (9y/10) = 850
⇒ 11x + 9y = 8500............... 1
in case 2
⇒ (x - x/10) + (y + y/10) = 950
9x + 11y = 9500 ................. 2
after solving equations 1 and 2 we will get
x = 200 and y = 700
∴cost of the chair is Rs 200 and the cost of the table is Rs 700 

Answer 2

Answer:

Cost of Chair = Rs. 200

Cost of Table = Rs. 700

Step-by-step explanation:

Let the cost of Chair be 'x'

& the cost of Table be 'y'.

CASE 1: Gain on Chair =

$\frac{10}{100} \times x \\ = \frac{x}{10}$

Loss on Table

$\frac{10}{100} \times y \\ = > (x + \frac{x}{10} ) + (y - \frac{y}{10} ) = 850\\ = > ( \frac{11x}{10} ) + ( \frac{9y}{10} ) = 850 \\ = > 11x + 9y + = 8500....eq(1)$

CASE 2:

$(x - \frac{x}{10} ) + (y + \frac{y}{10} ) = 950 \\ 9x + 11y = 9500......(2)$

Solving (1) &(2),

x=200,y=700

Cost of Chair=Rs. 200

Cost of Table=Rs. 700

Hope it will help.

PLZ LIKE IT....

If any problem comment me..