Math, asked by shallinipanjgotra68, 8 months ago

a man sold a toster at a profit of 10% had he purchased it for 5% less than its sold for rupees 56 more he would have gained 25% for how much did he pay​

Answers

Answered by mddilshad11ab
99

\sf\large\underline{Let:}

  • \rm{Cost\: price\:_{(roster)}=x}

\sf\large\underline{To\: Find:}

  • \rm{Cost\: price\:_{(roster)}=?}

\sf\large\underline{Solution:}

\sf\small\underline{Given,\:in\:case\:(i):}

\rm{A\:man\:sold\:a\:toster\:at\:a\:profit\:of\:10\%}

\tt{SP=\dfrac{100+G\%}{100}\times\:CP}

\tt{SP=\dfrac{100+10}{100}\times\:x}

\tt{SP=\dfrac{110x}{100}}

\tt{SP=\dfrac{11x}{10}------(i)}

\sf\small\underline{Given,\:in\:case\:(ii):}

  • had he purchased it for 5% less than its sold for rupees 56 more]

\tt{\implies SP=\dfrac{100-L\%}{100}\times\:CP}

\tt{\implies SP=\dfrac{100-5}{100}\times\:x}

\tt{\implies SP=\dfrac{95x}{100}+56------(ii)}

  • solving equations 1 and 2 here]

\tt{\implies \dfrac{11x}{10}=\dfrac{95x}{100}+56}

\tt{\implies \dfrac{11x}{10}-\dfrac{95x}{100}=56}

\tt{\implies \dfrac{110x-95x}{100}=56}

\tt{\implies 15x=5600}

\tt{\implies x=373.33}

\sf\small\underline{Given,\:in\:case\:(iii):}

  • he would have gained 25% for how much did he pay]

\tt{\implies CP\:_{(for\: him)}=\frac{100-25}{00}\times\:373.33}

\tt{\implies CP\:_{(for\: him)}=\frac{75}{100}\times\:373.33}

\tt{\implies CP\:_{(for\: him)}=279.99}

Answered by Glorious31
8

Given

  • Selling Price = 10% profit

  • Cost price = 5% less than Selling Price

To find :

If he would have sold it for Rs. 56/- more ;

he would have got 25% profit on the Cost price. ( cost price is the amount he payed or amount for which he had bought the toaster.)

Solution :

Let us consider the cost price of the toaster as : X

We have been told that he had got a profit of 10% when he sold that.

It means SELLING PRICE : \rm{ x + (\dfrac{10}{100})x}

So we get the selling price as :

1.1x

COST PRICE : 5% less . so ,

\rm{ x - \dfrac{5}{100}x }

So , we get the Cost price as :

0.95x

If he had sold for Rs. 56/- more ; he would have got a profit of 25%

So , 1.1x + 56 = profit of 25%

SELLING PRICE :

\rm{ 0.95x + (\dfrac{25}{100})0.95x }

\implies{\rm{ 1.25 \times 0.95x}}

When we bring the first and second selling prices together we get the equation :

\longrightarrow{\rm{ 1.25 \times 0.95x = 1.1x \times 56}}

\longrightarrow{\rm{ 0.0875x = 56}}

Here we have taken approximate value i.e. the nearest value of multiplication as the amount cannot be negative.

\longrightarrow{\rm{ x = 640}}

\large{\implies\boxed{\rm{ CP = Rs. 640/-}}}

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