Math, asked by 17Mahakshah, 4 months ago

A man sold half of his land he gave 1/3of remaining to his son and 1/4 of the balance to his daughter what fraction of his land is now left with him​

Answers

Answered by advitabhat23
6

Answer:

1/24

Step-by-step explanation:

Man sold half of the land.

∴1/2 of the land is remaining.

He gave remaining 1/3 to his son.

=\frac{1}{3}* \frac{1}2}=\frac{1}{6}

∴1/6 of the land is remaining.

He gave 1/4 of the balance to his daughter.

=\frac{1}{4}* \frac{1}{6} =\frac{1}{24}

∴1/24 of the land is remaining.

The man had 1/24 of the land remaining with him.

hopw it helps! Please mark as brainliest :-)

Answered by sangmamaraksangma28
1

Step-by-step explanation:

let's assume man's land as 1.

land sold by him = half of his land (i.e. 1/2)

so land left with him =1/2

A/Q,

Share of his son =1/3 of 1/2

=1/6

Share of his daughter = 1/4 of (1/2 - 1/6)

= 1/4 × 2/6

= 1/12

Land left with him = land sold - share of son - share of

daughter

= 1/2 - 1/6 - 1/12

= 6 - 2 - 1/12

= 3/12

= 1/4

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