A man sold his bicycle for ₹405 losing 1/10 of its cost price.find it's cost price
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Answered by
7
A man sold his bicycle for ₹405
let the cost price x
he looses x/10 rupees when he sold it.
so his selling price = x-(x/10)=9x/10
so the eq is
9x/10=405
x= 450
the actual cost of the bicycle is 450 rupees
let the cost price x
he looses x/10 rupees when he sold it.
so his selling price = x-(x/10)=9x/10
so the eq is
9x/10=405
x= 450
the actual cost of the bicycle is 450 rupees
vjchandrumouli:
Thank u
Answered by
4
Answer:
C.P = 450 , Loss = 10%
Step-by-step explanation:
Le the C.P. be Rs x
Loss = 1/10 of x = x/10
S.P. = C.P. - Loss
⇒ x - x/10
⇒9x /10
Also S.P. = 405
So, 9x/10 = 405
⇒ 9x = 405 × 10
⇒ 9x = 4050
⇒ x = 4050/9
⇒ x = 450
So, C.P = 450
Loss = x/10 = 450/10 = 45
Loss % = (45 × 100) / 450 = 10%
Hence, Required answer is C.P = 450 , Loss = 10%
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