Question

a man sold two articles at rupees 25920 eat these was sold at 8% gain and 4% loss respectively find the gain or loss percent in the whole transaction

Answer 1

SP of first article = Rs.25920
Gain% = 8%
CP of first article = 100/100+Gain%×SP
100/100+8×25920
100/108×25920 = Rs.24000
SP of second article = Rs.25920
Loss% = 4%
CP of second article = 100/100-Loss%×SP
100/100-4×25920
100/96×25920 = Rs.27000
Total SP of the two articles = 25920×2 = Rs.51840
Total CP of the two articles = 27000+24000 = Rs.51000
Since (SP) > (CP) there is gain in whole transaction
Gain = (51840-51000) = 840
Gain% = (Gain/Total CP ×100)%
(840/51000×100)%
1.64705882%

Answer 2

Answer:

First article.....

SP= 25920

gain = 8%

let CP be x

gain= 8% of x

= 8/100 × x = 2x/25

ATP

SP= CP + gain

= x + 2x/ 25

= 27x/25

therefore, 27x = 25 × 25920

x= 25× 25920/ 27 = 24000

Second article......

loss= 4%

let CP be y

Loss = 4% of y

= 4/100 × y

= y/ 25

ATP,

SP= CP - loss

therefore, 25920 = y - y/25

25920= 24y/25

y = 25× 25920/ 24

= 27000

then, total CP = 24000+ 27000 = 51000

therefore, total SP = 25920 + 25920 = 51840

GAIN = SP - CP = 51840 - 51000

= 840

gain% = G/CP × 100

= 840/ 51000 × 100 = 28/17

= 1 hole 11/17% ANS