Question

A man sold two articles for RS.4560 each on selling first he gains 20% and on the other he loss 30%. What is overall profit or loss percent in this transaction.

Answer 1

Answer:

$loss \: = \: \frac{2}{32} \times 100 = \: 6\frac{1}{4} percent$

hope it helps

Answer 2

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Given :

The selling price of each two article = Rs 4560

The gain% on first article = 20%

The loss% on other article = 30%

To Find :

The overall profit or loss percent in this transaction

Solution :

Let The selling price of article at 20% gain = $s.p1s.p_1s.p$

Let The cost price of article at 20% gain = $c.p1c.p_1c.p$

Let The selling price of article at 30% loss = $s.p2s.p_2s.p$

Let The cost price of article at 30% loss = $c.p2c.p_2c.p$

Gain% = $s.p−c.pc.p\dfrac{s.p-c.p}{c.p}$

So, 20% = $s.p1−c.p1c.p1\dfrac{s.p_1-c.p_1}{c.p_1}$

Or, $120100\dfrac{120}{100}$

= $s.p1c.p1\dfrac{s.p_1}{c.p_1}$

Or, $120100\dfrac{120}{100}$

= $4560c.p1\dfrac{4560}{c.p_1}$

∴ $c.p1c.p_1c.p$

= Rs 3800

Again

Loss% = $c.p−s.pc.p\dfrac{c.p-s.p}{c.p}$

So, 30% = $c.p1−s.p1c.p1\dfrac{c.p_1-s.p_1}{c.p_1}$

Or, $70100\dfrac{70}{100}$

= $s.p1c.p1\dfrac{s.p_1}{c.p_1}$

Or, $70100\dfrac{70}{100}$

= $4560c.p2\dfrac{4560}{c.p_2}$

∴ $c.p2c.p_2c.p$

= Rs 6514

Now,

Total cost price of two articles = $c.p1c.p_1c.p$

Or, C.P = Rs 3800 + Rs 6514

∴ C.P = Rs 10314

i.e Total cost price of two articles = C.P = Rs 10314

∵ Selling price of each article = Rs 4560

So, Total Selling price of two articles = S.P = Rs 4560 + Rs 4560 = Rs 9120

Again

As cost price is more than selling price, so there is a loss in overall

Thus , Loss% = $C.P−S.PC.P\dfrac{C.P-S.P}{C.P}$

Or, Loss% = $Rs10314−Rs9120Rs10314\dfrac{Rs 10314-Rs 9120}{Rs 10314}$

Or,

Loss% = RS 1194/Rs 10314

∴ Loss% = 11.57

Hence, The overall loss% in this transaction is 11.57%