a man sold two cars at rs. 99000 each. on one he gains 10% and on other loses 10% .hiw much does he gain or lose on his whole transaction? also,calculate it in percentage
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Answered by
176
SP of both cars = ₹99000
For the first car, he gains 10%
Thus CP = [SP/(100 + gain %)] × 100
=> CP = [99000/(100+10)] × 100
=> CP = ₹ 90000
For the second car, he loses 10%
Thus CP = [SP/(100 - loss %)] × 100
=> CP = [99000/(100-10)] × 100
=> CP = ₹ 110000
Total Cost price = 110000+90000 = ₹200000
Total selling price = 99000×2 = ₹198000
Total loss = 200000-198000 = ₹2000
loss % = 2000/200000 × 100 = 1 %
Thus, he loses 1% in whole transaction.
For the first car, he gains 10%
Thus CP = [SP/(100 + gain %)] × 100
=> CP = [99000/(100+10)] × 100
=> CP = ₹ 90000
For the second car, he loses 10%
Thus CP = [SP/(100 - loss %)] × 100
=> CP = [99000/(100-10)] × 100
=> CP = ₹ 110000
Total Cost price = 110000+90000 = ₹200000
Total selling price = 99000×2 = ₹198000
Total loss = 200000-198000 = ₹2000
loss % = 2000/200000 × 100 = 1 %
Thus, he loses 1% in whole transaction.
TheUrvashi:
nice one....
Answered by
69
this is your right answer
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