A man sold two cars for Rs 99000 each one he gain 10% and on the other a loss of 10% find his overall gain or loss in the transaction
Answers
Answer:
- He loses 1% in whole transaction.
Given :
- A man sold two cars for Rs 99000 each one he gain 10%.
- The other a loss of 10%.
To find :
- His overall gain or loss in the transaction =?
Step-by-step explanation:
SP of both cars = ₹99000 [Given]
For the first car, he gains 10%
We have to find C. P of first car,
Thus,
CP = [SP/(100 + gain %)] × 100
Substituting the values in the above formula, we get,
CP = [99000/(100+10)] × 100
CP = 99000/110 × 100
CP = ₹ 90000
And, For the second car, he loses 10%
Now, We have to find C. P of second car,
Thus
CP = [SP/(100 - loss %)] × 100
Substituting the values in the above formula, we get,
CP = [99000/(100-10)] × 100
CP = 99000 / 90 × 100
CP = ₹ 110000
Now,
Total Cost price = C. P of first car + C. P of second car.
Substituting the values, we get,
110000 + 90000 = ₹ 200000
Total selling price = S. P × 2
Substituting the values, we get,
99000 × 2 = ₹198000
We can see that, C. P > S. P
So, it happens loss.
Now,
Total loss = C. P - S. P
Substituting the values, we get,
200000 - 198000 = ₹2000
Loss % = loss/C. P × 100
= 2000/200000 × 100
= 1 %
Thus, He loses 1% in whole transaction.
Case l
SP= 99,000
Gain =10%
CP of car=(100/100+gain%)×SP
= (100/110)×99,000
=90,000
Case ll
SP= 99,000
Loss =10%
CP of car=(100/100-Loss%)×SP
= (100/90)×99,000
=1,10,000
Total CP= 90,000+1,10,000=Rs. 2,00,000
Total SP= 2×99,000=Rs. 1,98,000
Loss= 2,00,000-1,98,000=Rs. 2000