A man sold two horses for rs. 29700 each. On one he lost 10% while he gained 10% on the other. Find his total gain or loss percent in the transaction.
Answers
Answered by
31
Solutions :-
We have
A man sold of two horses for Rs 29700 each.
Cost Price of one horse at 10% loss = (S.P × 100)/(100 - loss)
= (29700 × 100)/(100 - 10)
= 2970000/90
= 33000
Cost Price of other horse at 10% gain = (S.P × 100)/(100 + gain)
= (29700 × 100)/(100 + 10)
= 2970000/110
= 27000
Total cost price of two horses = Rs (33000 + 27000) = Rs 60000
Total selling price of two horses = Rs (29700 + 29700) = Rs 59400
Selling price < Cost Price
Loss = S.P - C.P
= Rs (60000 - 59400)
= Rs 600
Loss % = (loss × 100)/C.P %
= (600 × 100)/60000 %
= 60000/60000 %
= 1 %
Answer : Total loss percent in the transaction = 1%
We have
A man sold of two horses for Rs 29700 each.
Cost Price of one horse at 10% loss = (S.P × 100)/(100 - loss)
= (29700 × 100)/(100 - 10)
= 2970000/90
= 33000
Cost Price of other horse at 10% gain = (S.P × 100)/(100 + gain)
= (29700 × 100)/(100 + 10)
= 2970000/110
= 27000
Total cost price of two horses = Rs (33000 + 27000) = Rs 60000
Total selling price of two horses = Rs (29700 + 29700) = Rs 59400
Selling price < Cost Price
Loss = S.P - C.P
= Rs (60000 - 59400)
= Rs 600
Loss % = (loss × 100)/C.P %
= (600 × 100)/60000 %
= 60000/60000 %
= 1 %
Answer : Total loss percent in the transaction = 1%
Answered by
2
Answer:
1%
Step-by-step explanation:
to solve this type of question there is a simple formula that is -(x^2)/100
given in the ques 10% gain as well as loss so
= -(10^2)/100
= -100/100
= -1%
where -(minus) represent loss.
Hope it will help you.
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