a man sold two radios at Rs 4800 each. on one he gains 20% and on the other He loses 20% find gain and loss in the whole transaction .
Please Do it by the easiest method
help me guys plzz
Answers
Answer:
Hello!❤️
Step-by-step explanation:
total s.p=4800*2=9600
first radio
HE SOLD AT GAIN OF 20%
c.p= (4800*100)/120
=4000
second radio
HE SOLD AT loss OF 20%
c.p=(4800*100)/80
=6000
total cost price=10000
total s.p=9600
loss=400
loss%=(400*100)/10000
loss%=4%
#Thankyou
#Thank my answers!!!
Answer:
Here is the answer to your question.
Given, the selling price of each radio is Rs 4800.
Let Rs x and Rs y be the cost price of the two radios.
Gain on selling one radio = 20%.
Step-by-step explanation:
∴ S.P. – C.P. = 20% of C.P.
4800-x = (20/100)x
x+(1/5)x = 4800
6x/5=4800
x = (4800×5)/6
x = 4000
loss on selling the other radio = 20%
∴C.P - S.P. = 20% of C.P.
y-4800 = (20/100)y
y-y/5 = 4800
4y/5 = 4800
y = (4800×5)/4
y = 6000
total cost price of two radios = 4000 + 6000 = Rs. 10000
total selling price of two radios = 2 × 4800 = Rs. 9600
since, total cost price of two radios is greater that total selling price of two radios.
∴ man suffer loss in the total transaction
loss = Rs.10000 - Rs.9600 = Rs.400
∴ loss% = (loss of whole transaction /total cost price of two radios) × 100
= (400/10000) × 100 = 4%
Hope it helps !