Question

A man sold two radios at Rs. 4800 each. On one he gains 20% and on the another

he loses 20% . Find the gain or loss percent in the whole transaction.
​

Answer 1

Answer:-

Given:

SP of first Radio = Rs. 4800

Gain% on first radio = 20%

We know that,

CP = (100/100 + gain% ) * SP

Hence,

⟹ CP of first Radio = (100/100 + 20) * 4800

⟹ CP of first Radio = 100 * 4800/120

⟹ CP of first Radio = Rs. 4000

Similarly,

SP = (100 - loss%/100) * CP

⟹ 4800 = (100 - 20/100) * CP of second Radio

⟹ 4800 * 100/80 = CP of second Radio

⟹ Rs.6000 = CP of second Radio

Now,

• Total SP of radios = 4800 + 4800 = Rs. 9600

• Total CP of radios = 4000 + 6000 = Rs. 10000.

We observe that,

CP > SP

So, a loss is occured.

⟹ Loss = CP - SP

⟹ Loss = 10000 - 9600

⟹ Loss = Rs. 400

Now,

Loss% = (Loss/CP) * 100

⟹ Loss% = 400/10000 * 100

⟹ Loss% = 4%

∴ The loss occurred in the whole transaction is 4 %.

Answer 2

$\huge \tt \underline{solution}$

$\tt{SP \: of \: one \: fan = Rs \: 990}$

$\tt{Gain \: percentage \: = 10\%</p><p>}$

$\\ \tt{its \: cp = (\frac{100}{100 - loss} \times sp)}$

$\\ \tt{ = (\frac{100}{100 - 10} \times 990)}$

$\\\tt{ (\frac{ \: 100 \: }{ \: 90 \: } \times 900)} = rs \: 1100$

$\tt{Total \: CP \: of \: the \: two \: fans} \\ \tt{ = Rs (900 + 1100) = Rs 2000}$

$\tt{Total \: SP \: of \: the \: two \: fans \: } \\ \tt{= Rs (990 + 990) = Rs 1980}$

$\tt{Since \: CP \: >SP, \: there \: is \: a \: loss \: } \\ \tt{ in \: the \: whole \: t ransaction.}$

$\\\tt{Nowloss=Rs2000 -1980= rs 20}</p><p>$

$\tt{loss=(\frac{loss}{cp}) \times 100}$

$\tt{loss\:percent = 4\:percent}$

$\tt \underline{Hence, \: the \: shopkeeper \: incurs \: } \\ \tt \underline{ a \: loss \: of \: in \: the \: whole} \\ \tt \underline{ transaction \: }$