Math, asked by krunal2508, 10 months ago

a man sold two radios for 2000 Rs. each. one he gains 16% and on other he losses 16% . find gains or loss percent in the transition. ​

Answers

Answered by Topperworm
0

selling price of each radios =Rs 2000

let the cost price of first radio be 'x' .

selling price of first radio = Rs 2000

gain on first radio = 16 %

cost price of first radio:

x + 16% of x = 2000

x + 0.16x = 2000

1.16x = 2000

x = Rs 1724.1

selling price of second radio = Rs2000

loss = 16 %

let the cost price of second radio be 'y'

y - 16 % of y = 2000

y - 0.16y = 2000

0.84y = 2000

y = 2380.9

the total cost price of two radios:

x + y = 1724.1 + 2380.9 = Rs 4105

total selling price of two radios:

= 2000 + 2000 = Rs 4000

loss = 4105 - 4000 = Rs 105

loss % = loss × 100 / total cost price

105 × 100 / 4105 = 2.5%

therefore, there was loss of 2.5% in the whole transaction.

Answer : loss = 2.5 %

Hope this helps

Answered by sailalitya3901
0

Answer:

2.5%loss

Step-by-step explanation:

on first radio:

selling price =2000₹

profit% =16%

cost price = (selling price×100)÷(100+profit%)

c.p=(2000×100)÷(100+16)

= 1724₹ (approximately)

on second radio

s.p=2000₹

loss%=16%

c.p=(s.p×100) ×(100-loss%)

c.p=(2000×100)÷(100 -16)

=2381₹(approximately)

total cost price:

1724+2381

=4105₹

total selling price:

2000+2000

=4000

since,cp >sp,he gained a loss.

total loss:

4105-4000=105₹

loss%:

l%=(loss÷c.p )×100

(105÷4105) ×100

=2.5%

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