Question

a man sold two scooter for 24000 each.on one he gained 20%and on the other he lost 20%.find the total loss or gain.

Answer 1

Solutions :-


Given :

A man sold two scooter for 24000 each.


Find the cost price of one scooter at gain of 20% :-

C.P = (S.P × 100)/(100 + gain)
= (24000 × 100)/(100 + 20)
= 2400000/120
= 20000

Find the cost price of other scooter at loss of 20% :-

C.P = (S.P × 100)/(100 - loss)
= (24000 × 100)/(100 - 20)
= 2400000/80
= 30000


Now, we have

Selling price of two scooter = Rs (24000 + 24000) = Rs 48000
Cost Price of two scooter = Rs (20000 + 30000) = Rs 50000


Cost Price is greater than the selling price. Therefore, Loss.


Loss = C.P - S.P
= Rs (50000 - 48000)
= 2000

Loss % = (loss × 100)/C.P %
= (2000 × 100)/50000 %
= 200000/50000 %
= 4 %


Hence,
Loss = 2000
Loss percent = 4%

Answer 2

Answer:

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