Question

A man speaks truth 3 out of 4 times. He throws a die and reports it to be a 6.
What is the probability of it being a 6?

Answer 1

I'll love to answer this
P[6rolled and reports as 6] =1/6*3/4 =1/8
P[non 6 and reports as 6] = 5/6*1/4=5/24
P[reported as 6]= 1/8+5/24=1/3
P[getting 6 according to the man's statement ] =[1/8]/[1/3]
=3/8