Question

A man spend 1/3 of his life as a bachelor.After 10 yrs of his marriage a son was born to him.The father and son died in an accident and at that time fathers age was double that of his son.What is the fathers age at the time of death

Answer 1

father age Is F
son age is S

At the time of death F=2S

1/3F+10+S=F
S=2/3*F-10

F=2S

S=4/3*S -10
1/3*S=10
S=30

F=2*30=60

Answer 2

Answer:

The age of father is 60 years

Step-by-step explanation:

Let us suppose the Father age is x years

And, Son's age is y years

According to question,

A man spend 1 /3 of his life as a bachelor

Also, After 10 years of his marriage a son was born to him

Therefore,

Age of father = 1/3 x + 10 + y  

x = 1/3x + 10 + y

y = 2x / 3 - 10

Also it is given,

At the time of death father's age was double that of his age of son, that is,

x = 2y

y = x / 2

Substituting the value of y as x/2,

x/2 = 2x/3 - 10

x/2 - 2x/3 = -10

( 3x - 4x ) / 6 = -10

- x = - 60

x = 60

Hence,

The age of father was 60 years