a man spend 20% on fooding 30% of rest on transport and 1/3 of rest on clothes.if he saves 2520 monthly then what is his monthly income?
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Let the salary of the man be Rs x
Amount spent on fooding = 20% of x
= (20/100) of x
= (1/5) × x
= x/5 Rs
Remaining money = x - x/5
= (5x-x)/5
= 4x/5 Rs
Amount of money spent on transport = 30% of the rest
= (30/100) of 4x/5
= (3/10) × (4x/5)
= 12x/50
= 6x/25 Rs
Amount saved = Rs 2520
Now we can write a relation as
x/5 + 6x/25 +2520 = x
⇒x/5 + 6x/25 - x = -2520
⇒ (5x + 6x - 25x)/25 = -2520
⇒ -14x/25 = -2529
⇒ -14x = -2520 ×25
⇒ -14x = -6300
⇒ x = -6300/ -14
∴ x =4500
Therefore the salary of the person is Rs 4500
Amount spent on fooding = 20% of x
= (20/100) of x
= (1/5) × x
= x/5 Rs
Remaining money = x - x/5
= (5x-x)/5
= 4x/5 Rs
Amount of money spent on transport = 30% of the rest
= (30/100) of 4x/5
= (3/10) × (4x/5)
= 12x/50
= 6x/25 Rs
Amount saved = Rs 2520
Now we can write a relation as
x/5 + 6x/25 +2520 = x
⇒x/5 + 6x/25 - x = -2520
⇒ (5x + 6x - 25x)/25 = -2520
⇒ -14x/25 = -2529
⇒ -14x = -2520 ×25
⇒ -14x = -6300
⇒ x = -6300/ -14
∴ x =4500
Therefore the salary of the person is Rs 4500
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