A man spend 3/8 of his monthly income and still has rupees 720 left with him. How much money he had initially
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Hey there !!
let the money he have first be rs x
given :- 3/8 of x he spent and left 720
now ,
x - 3x/8 = 720
(8x-3x)/8 = 720
5x/8 = 720
5x = 5760
x = 1152
hence he had 1152 rupees first .
verification ;-
=> 1152 - 3/8×1120
=> 1152 - 3 × 140
=> 1152 - 420
=> 720 hence , verified .
Step-by-step explanation:
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