Question

A man spends 2/5 of his money and is left with Rs 30. How much did he initially have

Answer 1

rupees 50

Step-by-step explanation:

this should help

Answer 2

Answer:

Initially he had 50 rupees.

Step-by-step explanation:

Given, a man spends 2/5 of his money.

Let total amount of money be x rupees.

Now question is what is the meaning of $\frac{2}{5} \: of \: x$

We know,

$\frac{a}{b} \: of \: c = \frac{a}{b} \times c$

By some examples,we can understand this concept.

Example -1:

$\frac{1}{2} \: of \: 50 \\ = \frac{1}{2} \times 50 \\ = 25$

Example-2:

$\frac{5}{2} \: of \: 100 \\ = \frac{5}{2} \times 100 \\ = 5 \times 50 \\ = 250$

In the given question,

$\frac{2}{5} \: of \: x \\ = \frac{2}{5} \times x \\ = \frac{2x}{5}\: rupees$

Now remaining money

$= (x - \frac{2x}{5} ) \\ = \frac{5x - 2x}{5} \\ = \frac{3x}{5} \: rupees$

It is also given amount of remaining money is 30 rupees.

So,

$\frac{3x}{5} = 30 \\ 3x = 30 \times 5 \\ x = \frac{30 \times 5}{3} \\ x = 10 \times 5 \\ x = 50$

Therefore initially he had 50 rupees.

This is a problem of Fraction.

Know more about Fraction,

1.https://brainly.in/question/9833636

2.https://brainly.in/question/16383044

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