Math, asked by DheerajMehlawat8270, 11 months ago

A man spends 25% of his income on house rent 45% of his income on food, and 40% of the balance on conveyance. If he is left with rs. 540, his income is

Answers

Answered by haridasan85
5

Answer:

House rent=25%

food=45%

Total = 70%

Remaining=100-70=30%

40% of 30 = 12%=connveyance

Total = 25+45 +12=82%

Remaining=100-82=18%

Let his income be X

Xxl8/100=540

x = 540x100/18 =3000

INCOME is Rs 3000

Answered by qwmagpies
1

Given:

A man spends 25% of his income on house rent 45% of his income on food, and 40% of the balance on conveyance. If he is left with rs. 540.

To find:

The income of the man.

Solution:

Let the income of the man is 100 rupees.

He spends 25% of his income on house rent and 45% of his income on food.

So, the total expenditure is 25+45=70%.

The remaining amount is 100-70=30.

He spends 40% of the balance on conveyance.

So, he spends 30×40/100=12 on conveyance.

Now he has 100-70-12=18 rupees.

18 rupees is equal to 540 rupees.

So, 100 rupees is equal to 540×100/18=3000.

The income of the man is 3000 rupees.

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