Question

a man spends 3 /8 of his money and steel has Rs. 720 left with him. how much money did he have at first? please give.its step by step explanation ​

Answer 1

Given

Man spends 3 / 8 of his money

Let us assume a man has Rs 1

Amount spent = 3 / 8 of 1

We get,

= Rs 3 / 8

Amount left = 1 – 3 / 8

We get,

= (8 – 3) / 8

= Rs 5 / 8

Since 5 / 8 of his total money = Rs 720

∴ Total money = Rs (720 × 8) / 5

= Rs 5760 / 5

= Rs 1152

Hence, total money a man has is Rs

Answer 2

Answer:

let total money be Rs x.

money spent 3/8 of x

money left

x- 3/8x=5x/8

5x/8= 720

5x = 720×8

x= 720×8/5

x= 144×8= 1152

total money = Rs. 1152.