Math, asked by AnanyaVinod, 22 days ago

A man spends 3/8 of his money and still has ₹80 left with him. How much money did he have at first?​

Answers

Answered by minakshijain967
1

Answer:

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Answered by TCS2006
0

Answer:

He had 128 rupees initially.

Step-by-step explanation:

Let the money he had be rupees x.

He spends 3/8 of his money.

So, money left with him = (1-3/8) x

= 5x/8

So, 5/8 of x = 80

5x/8 = 80

5x = 80 * 8

5x = 640

x = 640/5

x = 128

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