A man spends 3/8 of his money and still has ₹80 left with him. How much money did he have at first?
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He had 128 rupees initially.
Step-by-step explanation:
Let the money he had be rupees x.
He spends 3/8 of his money.
So, money left with him = (1-3/8) x
= 5x/8
So, 5/8 of x = 80
5x/8 = 80
5x = 80 * 8
5x = 640
x = 640/5
x = 128
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