A man spends 6.4KJ energy in displacing a body by 64m in the direction in which he applies force, in 2.5s. Calculate : (1) the force applied, and (2) the power spent (in H.P.) by the man.
Answers
Answered by
342
work done = energy spent = 6.4 KJ = 6400J
6400 = Force × Distance
Force = 6400/64 = 100 N
Power = Work done/Time = 6400/2.5 = 2560 watt = 2560/746= 3.43 HP
6400 = Force × Distance
Force = 6400/64 = 100 N
Power = Work done/Time = 6400/2.5 = 2560 watt = 2560/746= 3.43 HP
Answered by
122
Answer:
Explanation: work done by man= 6.4 kj
Distance move, s is 64 m
1) work done by the man = force×distance moved in direction of force
Work,w = f×d
6.4×10^3=f×64
f= 6.4×10^3/64 =100 N
2) power spent= 6.4×10^3/2.5 = 2560w
1 H.P = 746w
1w = 1/746 H.P
2560w = 2560/746 H.P = 3.43 H.P
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