Question

A man spends 64 kJ energy in displacing a body by
64 m in the direction in which he applies force, in
25 . Calculate : (i) the force applied, and (ii) the
power spent (in H.P.) by the man.​

Answer 1

Answer:

(1) E=F

so,Force=64×100newton=6400N

(2) H.P=Horse power

P=F/Sec

and you have not written the question wright it is 25 sec write it full.

H•P= 6400J÷25

" =256 watt.

Explanation:

thanks for a good question.

hope the answer will be helpfull to you.