Question

A man spends half of his salary on education of his children and one fourth on his household expense. If he saves Rs. 15,000 in a month, find his monthly salary.

Answer 1

$Let \: the \: monthly \: salary \:of \:a \:man = Rs\:x$

$Amount \: spent \:on \: education \:of \:his$

$children = \frac{x}{2}$

$Amount \: spent \:on \: household \: expenses$

$= \frac{x}{4}$

$Savings = Rs\:15000$

/* According to the problem given */

$x - \frac{x}{2} - \frac{x}{4} = 15000$

$\implies \frac{4x - 2x - x }{4} = 15000$

$\implies \frac{x }{4} = 15000$

$\implies x = 15000 \times 4$

$\implies x = Rs\:60,000$

Therefore.,

$\red{ Monthly \:salary \:of \:the \:man}$

$\green {= Rs\:60,000}$

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Answer 2

$\bf{\underline{\underline{\bigstar\bigstar\: Solution : }}}$

$\:$

$\footnotesize{Let, the \: monthly \: salary \: be \: x }$

$\:$

$\footnotesize{Money \: he \: spend \: on \: education = \dfrac{x}{2} }$

$\:$

$\rule{200}2$

$\:$

$\footnotesize{Money \: he \: spend \: on \: household = \dfrac{x}{4} }$

$\:$

$\rule{200}2$

$\:$

$\footnotesize{Money \: he \: saves = Rs. 15,000 }$

$\footnotesize{\implies x - \Big( \dfrac{x}{2} + \dfrac{x}{4} \Big) = Rs. 15,000 }$

$\footnotesize{\implies x - \Big( \dfrac{2x + x}{4} \Big) = Rs. 15,000 }$

$\footnotesize{\implies x - \dfrac{3x}{4} = Rs. 15,000 }$

$\footnotesize{\implies \dfrac{4x - 3x}{4} = Rs. 15,000 }$

$\footnotesize{\implies \dfrac{x}{4} = Rs. 15,000 }$

$\footnotesize{\implies x = Rs. 15,000 \times 4 }$

$\footnotesize{\implies x = Rs. 60,000 }$

$\:$

$\bold{Monthly \: salary \: is \: Rs. 60,000 }$