Question

a man spends ⅜ of his money and still has ₹ 720 left with him how much money did he have at first ​

Answer 1

• let the money he had beginning be “ y ”

then ,

$\large \sf \frac{3}{8} \times (y) = 720$

$\large \sf (y) = \frac{8}{ \cancel3} \times \: { \cancel{720}}^{ \: \: 240} \implies \: \: y = 8 \times 240 = 1920rs$

• The Man had ₹1920 in beginning

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Answer 2

Answer:

money he have at first =₹x

money spent by him=₹x3/8

money left with him=x-3x/8

720=5x/8

5x=720×8

x=144×8=

x=1152