A man spends Rs 1760 for buying trouser at Rs 280 each and shirts at Rs120 how many number of shirts he bought when maximum no of trousers he bought
Answers
6 trousers
1 shirt
Answer:
Number of shirts he bought = 3
Number of trousers he bought = 5
Step-by-step explanation:
Given,
A man spends Rs 1760 for buying trouser at Rs 280 each and shirts at Rs 120
Let the number of shirts be S and Trousers be T
According to question,
Cost of each trouser = Rs. 280
Cost of each shirt = Rs. 120
Therefore,
280 T + 120 S = 1760
28 T + 12 S = 176
7 T + 3 S = 44
T = ( 44 - 3 S ) / 7
Now,
We need to find the least value of S to make ( 44 - 3 S ) completely divisible by 7 to get maximum value of T
Taking S = 1
44 - 3 S / 7 = 44 - 3 / 7 = 41 /7 ≠ 0
Taking S = 2
44 - 3 S / 7 = 44 - 6 / 7 = 37 /7 ≠ 0
Taking S = 3
44 - 3 S / 7 = 44 - 9 / 7 = 35 /7 = 0
So ,
The value of S = 3
Value of T = ( 44 - 3 S ) / 7
Substituting value of S = 3
= 44 - 3 ( 3 ) / 7
= 44 - 9 / 7
= 35 / 7
= 5
Hence,
Number of shirts he bought = 3
Number of trousers he bought = 5