Math, asked by arjunpv3410, 6 months ago

A man spends two fifth of his money and rupees 13 is left how much had he initially

Answers

Answered by sarthak688
3

Answer:

by-step explanation:

Let \: initial \: money \: =Rs\:xLetinitialmoney=Rsx

\begin{gathered}\frac{2}{5} \:of \: initial\\money = \frac{2x}{5}\end{gathered}52ofinitialmoney=52x

Money \:left = Rs\:90Moneyleft=Rs90

\implies x-\frac{2x}{5}=90⟹x−52x=90

\implies \frac{5x-2x}{5}=90⟹55x−2x=90

\implies \frac{3x}{5}=90⟹53x=90

\begin{gathered}\implies x = 90\times \frac{5}{3}\\=30\times 5\\=Rs \:150\end{gathered}⟹x=90×35=30×5=Rs150

Therefore,

Initial \:money (x)=Rs\:150Initialmoney(x)=Rs150

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Answered by dhananjakumar754
0

Answer:

21.66........

Step-by-step explanation:

hope this answer will help you

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