A man spends two fifth of his money and rupees 13 is left how much had he initially
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Answer:
by-step explanation:
Let \: initial \: money \: =Rs\:xLetinitialmoney=Rsx
\begin{gathered}\frac{2}{5} \:of \: initial\\money = \frac{2x}{5}\end{gathered}52ofinitialmoney=52x
Money \:left = Rs\:90Moneyleft=Rs90
\implies x-\frac{2x}{5}=90⟹x−52x=90
\implies \frac{5x-2x}{5}=90⟹55x−2x=90
\implies \frac{3x}{5}=90⟹53x=90
\begin{gathered}\implies x = 90\times \frac{5}{3}\\=30\times 5\\=Rs \:150\end{gathered}⟹x=90×35=30×5=Rs150
Therefore,
Initial \:money (x)=Rs\:150Initialmoney(x)=Rs150
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Answer:
21.66........
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