Math, asked by raunaksingh50, 15 hours ago

A man spent 1/4 part of his income on food, 2/3 part 9n rent and the remaining Rs. 630 on other expenses. His house rent is

Answers

Answered by razeenrauf4
1

Answer:

Step-by-step explanation:

Total income = x

Money spent on food = 1/4 of x

Money spent on rent = 2/3 of x

1) Let us make the denominators same by LCM

LCM of 4 and 3 = 12

a) Money spent on food = 1 x 3 = 3

                                       4 x 3 = 12

1/4 = 3/12

b) Money spent on rent = 2 x 4 = 8

                                          3 x 4 = 12

2/3 = 8/12

2) Find out value of 1/12

3/12 + 8/12 = 11/12 = Money used

12/12 - 11/12 = 1/12 = Money left = Rs. 630

Total income = 1/12 x 12 = 12/12

630 x 12 = Rs. 7,560

3) Find rent

Rent = 2/3 = 8/12

1/12 = 630

8/12 = 630 = 8

= Rs. 5040

Final answer = Rs. 5040

Hope it helps

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Answered by harshithsaivemula14
1

Answer:

Rs. 5040

Step-by-step explanation:

Total income = x

Money spent on food = 1/4 of x

Money spent on rent = 2/3 of x

1) Let us make the denominators same by LCM

LCM of 4 and 3 = 12

a) Money spent on food = 1 x 3 = 3

                                      4 x 3 = 12

1/4 = 3/12

b) Money spent on rent = 2 x 4 = 8

                                         3 x 4 = 12

2/3 = 8/12

2) Find out value of 1/12

3/12 + 8/12 = 11/12 = Money used

12/12 - 11/12 = 1/12 = Money left = Rs. 630

Total income = 1/12 x 12 = 12/12

630 x 12 = Rs. 7,560

3) Find rent

Rent = 2/3 = 8/12

1/12 = 630

8/12 = 630 = 8

= Rs. 5040

Final answer = Rs. 5040

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