Math, asked by mohitrohit6313, 10 months ago

A man spent 10% of his money and aftelosing 30% of his remainder he had RS 1260 left. How much mone
y had he at first?

Answers

Answered by naavyya
5

Answer:

₹ 2000

Step-by-step explanation:

Let the amount the man had in the beginning be ₹ x.

Amount he spent = x * 10/100 = 0.1 x

Amount of remainder money = x - 0.1x = 0.9x

Amount of money he lost = 30% of 0.9x = 0.9x * 30/100 = 0.27x

Amount left with the man = x - 0.1x - 0.27x = 0.63x

According to the question,

0.63x = 1260

x = 1260/0.63

x = ₹ 2000

So, the man had ₹ 2000 at first.

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