Math, asked by srishtikumari642, 7 hours ago

A man spent 10% of his money and after losing 30% of his remainder he had Rs1260 left. How much money had he at first?​

Answers

Answered by samadritaghosh2008
3

Answer:

Let the amount the man had in the beginning be rs x.

Amount he spent = x * 10/100 = 0.1 x

Amount of remainder money = x - 0.1x = 0.9x

Amount of money he lost = 30% of 0.9x = 0.9x * 30/100 = 0.27x

Amount left with the man = x - 0.1x - 0.27x = 0.63x

According to the question,

0.63x = 1260

x = 1260/0.63

x = rs 2000

So, the man had rs 2000 at first.

Step-by-step explanation:

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