Question

A man spent 10%of his money and after losing 30% of his remainder he had rs 1260 left. Hwo much money had he at first?

Answer 1

Step-by-step explanation:

Ans rs. 2000

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Answer 2

Concept introduction:

Reaminder money is that money which remains in the hands after spending some of ther total money.

Given:

Here it is given that he spend $10$‰ of the money then he loses about $30$‰ of the money then the remainder is $1260$.

To find:

We have to find how much money had he at first?

Solution:

According to the problem, we assume that the man had $x$ amount money at first.

After spending first $10$‰ he have

$(x-\frac{x}{10} )\\=\frac{9x}{10}$

After loosing $30$‰ the remainder the amount left is

$(\frac{9x}{10})-[(\frac{9x}{10} *\frac{30}{100} )]\\=((\frac{9x}{10})-(\frac{27x}{100})\\ =\frac{63x}{100}$

∴$\frac{63x}{100} \\=1260$

∴$x=2000$

Money he had at first is $2000$.