Math, asked by arushisahotra02, 24 days ago

A man spent 12×1/2% of his money and he is left with ₹140.How much money had he at first?​

Answers

Answered by divyaprakash14060
1

Answer:

₹160

Step-by-step explanation:

Let the money he had at first be x.

A.T.Q.

x =  12 \frac{ \frac{1}{2} }{100}x  + 140

Now,

x =  \frac{25}{2}   \div 100x + 140

Then,

x =  \frac{25}{2}  \times  \frac{1}{100}x  + 140

x =  \frac{1}{2}  \times  \frac{x}{4}  + 140

x =  \frac{x}{8}  + 140

x =  \frac{x + 1120}{8}

8x = x + 1120

8x - x = 1120

7x = 1120

x =  \frac{1120}{7}

x = 160

Therefore, The money he had at first was ₹160.

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