Question

a man spent 121/2 % of his money and he is left with ₹ 140 . How much money had he at first

Answer 1

,Hi ...dear.
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#shubhendu

Answer 2

Answer:

₹160

Let the money he had at first be x.

A.T.Q.

x = 12 \frac{ \frac{1}{2} }{100}x + 140x=1210021x+140

Now,

x = \frac{25}{2} \div 100x + 140x=225÷100x+140

Then,

x = \frac{25}{2} \times \frac{1}{100}x + 140x=225×1001x+140

x = \frac{1}{2} \times \frac{x}{4} + 140x=21×4x+140

x = \frac{x}{8} + 140x=8x+140

x = \frac{x + 1120}{8}x=8x+1120

8x = x + 11208x=x+1120

8x - x = 11208x−x=1120

7x = 11207x=1120

x = \frac{1120}{7}x=71120

x = 160x=160

Therefore, The money he had at first was ₹160.