Question

A man, standing 300 m away from a hill, fires a gun. If he hears two sounds at the interval of 2 sec, what is thespeed of sound (in m/s) ?


pls answer fast​

Answer 1

Distance of person from nearer cliff, (d1)

=2v×t⇒d1=2330×3=495m

Distance of person from farther cliff, d2=2v×t

d2=2330×5=825m

Total distance between two cliffs

=d1+d2

=(495+825)

=1320m.

Answer 2

Answer:

Distance of person from nearer cliff, (d

1

)

=

2

v×t

⇒d

1

=

2

330×3

=495m

Distance of person from farther cliff, d

2

=

2

v×t

d

2

=

2

330×5

=825m

Total distance between two cliffs

=d

1

+d

2

=(495+825)

=1320m.