A man standing at some distance from a cliff hears the echo of the sound after 2seconds .he walks 495meters away from the cliff.he produces a sound there and receives the echo after 5sec .what is the speed of the sound ?
Answers
Hello user!
Answer is 330 m/s.
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Step by step solution:-
The initial distance of person from the cliff be xm.
Time taken to hear echo= 2seconds.
let speed of sound be v m/s.
Using formula, velocity= 2* distance/time
v = 2* x / 2
v= x......(1)
Now, the person moves 495 metres away from the cliff.
So , the distance becomes (x+495)
Time taken to hear the echo = 5 seconds.
therefore, v = 2* ( x +495)/5
putting value of x = v from eq. 1
v = 2*(v+495)/5
v= (2v + 9 9 0)/5
5 v = 2v + 990
3 v = 990
v = 330 m/s
Hope it helps ❤ ❤
Answer:
Answer is 330 m/s.
___________________________
Step by step solution:-
The initial distance of person from the cliff be xm.
Time taken to hear echo= 2seconds.
let speed of sound be v m/s.
Using formula, velocity= 2* distance/time
v = 2* x / 2
v= x......(1)
Now, the person moves 495 metres away from the cliff.
So , the distance becomes (x+495)
Time taken to hear the echo = 5 seconds.
therefore, v = 2* ( x +495)/5
putting value of x = v from eq. 1
v = 2*(v+495)/5
v= (2v + 9 9 0)/5
5 v = 2v + 990
3 v = 990
v = 330 m/s
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Explanation: