Question

A man standing between 2 parallel cliffs fires a gun. He hear 2 echos one after 2 seconds and other after 4 seconds what is the distance between cliffs if the speed of sound in air is 330m/s

Answer 1

Given,

t1=2s

t2=2+4

=6s

V=330m/s

We know,

V=2d/t

d1=Vxt/2

=330×2/2

=330m

d2=V×t/2

=330×6/2

=990m

Distance between two cliffs=330+990

=1320m

Answer 2

Given:

$t_1=2 s$

$t_2=4 s$

Speed of sound,v=330 m/s

To find:

The distance between cliffs

Solution:

$t_1+t_2=2+4$

$t_1+t_2=6 s$

We know that

Distance between two cliffs=$x_1+x_2=\frac{v(t_1+t_2)}{2}$

Using the formula

Distance between two cliffs

=$x_1+x_2=\frac{330\times 6}{2}$

=$990 m$

Hence, the distance between two cliffs=990 m