Question

A man standing between two cliffs, claps his hands and starts hearing a series of echoes at intervals of one second. if the speed of sound in air is 340 ms-1, the distance between the cliffs is

Answer 1

Given speed of sound in air C=340 m/s

Time interval of successive echoes t=1 seconds.

Thus distance traveled by the sound = C× t= 340×1=340 m

Now in 1 second the sound travel twice the distance between the two cliffs.

Hence, the distance between the two cliffs s =340÷2 =175 m

Answer 2

Answer:

495 m

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