Question

A man, standing between two cliffs, claps his hands and starts hearing a series of echoes at intervals of one second. If the speed of sound in air is 340ms−1, the distance between the cliffs is.........ans 340

Answer 1

2d=v×t

d=340×1/2

d=175

distance b/n two Cliff is 175+175 = 340m

Answer 2

2d=v×t

d=340×1/2

d=175

distance b/n two Cliff is 175+175 = 340m

Please mark my answer as brainliest.