Question

A man standing between two parallel cliffs fires a gun. He hears two echoes, one after 2 seconds and the other after 4 seconds. What is the distance between the cliffs if the speed of sound in air is 330 m/s ?​

Answer 1

Answer:

410m/s & 450m/s

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Answer 2

$\huge\underline\frak{\fbox{AnSwEr :-}}$

$\implies$ 990 m

Data : -

$\large\sf{t_1}$ = 2 s , $\large\sf{t_2}$ = 4 s , v = 330 m/s

Let $\large\sf{s_1}$ and $\large\sf{s_2}$be the distance of the two cliffs from the man

Time taken by sound to cover the l distance between the man and a cliff

$\leadsto$ $\large\sf\frac{1}{2} \times \:time \:for \:echo$

distance between the man and the first cliff is

$\large\leadsto$$\large\sf{s_1}$ = v $\large\sf\frac{t_1}{2}$ = (330 m/s) $\large\sf\frac{2s}{2}$ = 330 m

and the distance between the man and the second cliff is

$\large\sf{s_2}$ = v $\large\sf\frac{t_2}{2}$ = (330 m/s) $\large\sf\frac{4s}{2}$ = 660 m

$\large\leadsto$The distance between the two parallel cliffs

$\implies$ 330 m + 660 m = 990 m