A man standing between two parallel hills, fires a gun and hears two echoes, one 2s and the other 3s after the firing. If the velocity of the sound is 330m/s then find the difference between the two hills.
Plz help me.Today is my exam and the question is very inportant. Plz help.
lf anyone write correctly then l will mark his/her answer as a brainliest answer.
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Answer:
Distance=speed ÷time
Let the first Time be 2 s.
D=3.30÷2=165m
Let the 2nd time be 3s
D=330 ÷3=1 10m
Now first-2nd = 165-11o=55mts
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